Question

Prove:
sec 0 (1 – sin 0) (sec 0 + tan 0) = 1​


plz answer..

Answer 1

Step-by-step explanation:

LHS = sec theta (1-sin theta) (sec theta+tan theta)

= 1/cos theta(1-sin theta) (1/cos theta + sin theta/ cos theta)

=1-sin theta/cos theta(1+ sin theta/ cos theta)

=1-sin²theta/cos²theta

=cos²theta/cos²theta

=1

RHS = 1

LHS=RHS

Hence

Proved.