Question

Prove :

sec θ √(1 - sin2θ)  =  1

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Answer 1

Solution :

Let A = sec θ √(1 - sin2θ) and B = 1.

A = sec θ √(1 - sin2θ)

Because sin2θ + cos2θ = 1, we have

cos2θ = 1 - sin2θ

Then,

A = sec θ √cos2θ

A = sec θ ⋅ cos θ

A = sec θ ⋅ (1/sec θ)

A = sec θ / sec θ

A = 1

A = B (Proved)

Answer 2

hope it would help uh guys!!!!