Prove :
√sec*20 + cosec*20 = tan 0 + cot 0.
Please provide detailed explanation!
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sec² A = tan² A + 1 and
cosec² A = cot² A + 1
On Adding these , we get :
sec² A + cosec² A = tan² A + cot² A + 2
sec² A + cosec² A = tan² A + cot² A + 2 tan A cot A = ( tab A + cot A ) ²
√ sec² A + coses² A = tan A + cot A
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