Question

Prove
(sec teta-tan teta)² = 1-sin teta / 1 + sin teta
​

Answer 1

Answer:

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Answer 2

In R.H.S.,

(We know, Sin2 theta+ Cos2 theta is 1)

So, multiplying both numerator and denominator by (1-Sin theta) we get,

= 1-sin theta × 1- sin theta/ 1+ sin theta × 1-sin theta

= (1-sin theta)^2/ 1-sin theta

= (1- sin theta/cos theta)^2

= 1/cos theta - sin theta/cos theta

= (sec theta-tan theta)^2 = L.H.S.

Hope it helps.....^•^