prove(secA + tan A -1)(secA-tanA+1)=2tanA
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Given : (secA + tanA - 1)(secA - tan A + 1)
= > sec^2A - secAtanA + secA + secAtanA - tan^2A + tanA - secA + tanA - 1
= > -1 + sec^2A - tan^2A + 2tanA
We know that sec^2A - tan^2A = 1
= > -1 + 1 + 2tanA
= > 2tanA
Hope this helps!
= > sec^2A - secAtanA + secA + secAtanA - tan^2A + tanA - secA + tanA - 1
= > -1 + sec^2A - tan^2A + 2tanA
We know that sec^2A - tan^2A = 1
= > -1 + 1 + 2tanA
= > 2tanA
Hope this helps!
siddhartharao77:
Gud luck!
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4
Hello friend
Your answer is in the given attachment
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Your answer is in the given attachment
I hope it will help you
Thanks
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