Math, asked by sabikakhatun007, 4 months ago

Prove :-. (sin^2 A - sin^2 B)÷ (sinA . cosA - sinB .cosB) = tan (A + B ) please no any spam please answer fast.

Answers

Answered by harshitha7256

0

Answer:

Prove that:sin²A−sin²B(sinAcosA)−(sinBcosB)=tan(A+B)

Jun 7, 2018

LHS=sin²A−sin²B(sinAcosA)−(sinBcosB)

=2sin(A+B)sin(A−B)(2sinAcosA)−(2sinBcosB)

=2sin(A+B)sin(A−B)sin2A−sin2B

=2sin(A+B)sin(A−B)2cos(A+B)sin(A−B)

=tan(A+B)=RH

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