prove sin^2 + cos^2 = 1
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in triangle ABC right angled at B
we have,
AB² + BC²= AC²
dividing each term by (1) by AC²
we get,
AB² + BC² = AC² ( the whole divided by AC²)
(cos A)² + (sin A)² = 1
so cos²A + sin²A = 1
we have,
AB² + BC²= AC²
dividing each term by (1) by AC²
we get,
AB² + BC² = AC² ( the whole divided by AC²)
(cos A)² + (sin A)² = 1
so cos²A + sin²A = 1
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