Prove: sin 2 θ+cos 2θ=1
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Let a, b, c be lengths of right angled triangle
By definition
sinθ=b/c( hypotenuseopposite side )
cosθ=a/c( hypotenuse adjacent side )
sin 2 θ+cos 2 θ= c 2
b
2
+
c
2
a
2
=
c
2
a
2
+b
2
From Pythagoras theorem
c
2
=a
2
+b
2
∴
c
2
a
2
+b
2
=1
sin
2
θ+cos
2
θ=1
Hence, proved.
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1
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