Prove sin 2 theta + Cos 2 theta = 1
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The question is wrong.
The theta for which the value is 1 is given by nπ/4 where n is any integer
The theta for which the value is 1 is given by nπ/4 where n is any integer
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Answer:Consider a right-angled triangle, ΔABC, where ∠BAC=θ,

By the Pythagorean theorem,AC2+BC2=AB2Dividing by AB2,⇒AC2AB2+BC2AB2=AB2AB2⇒(oppositehypotenuse)2+(adjacenthypotenuse)2=AB2AB2=1⇒sin2θ+cos2θ=1
Step-by-step explanation:
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