Prove Sin(2X) = 2Sin(X) Cos(X)
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Step-by-step explanation:
we know,
one important identity ,
sin( A + B) =sinA.cosB + cosA. sinB
let A = x
B = x
then,
sin( x + x ) = sinx.cosx + cosx .sinx
sin2x = 2sinx.cosx
verify :-
Let x = 30°
LHS = sin60° = √3/2
RHS = 2sin30°.cos30° = 2× 1/2 × √3/2 =√3/2
LHS = RHS
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