Question

Prove (sin^3theta + cos^3theta) = (sintheta + costheta) (1-sintheta.costheta)

Answer 1

Step-by-step explanation:

LHS = ( sin^3θ + cos^3θ )

a^3 + b^3 = (a + b)(a^2 - ab + b^2)

= (sinθ + cosθ) ( sin^2θ - sinθ.cosθ + cos^2θ)

sin^2θ + cos^2θ = 1

= ( sinθ + cosθ )( 1 - sinθ .cosθ )

= RHS

hence proved (☺️)

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Answer 2

Step-by-step explanation:

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