Prove
Sin^4 theta - Cos^4 theta=2 Sin^2 theta=1
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Step-by-step explanation:
given,
sin^4A-cos^4A
a^2-b^2=(a+b)(a-b)
(sin^2A)^2-(cos^2A)^2
(sin^2A+cos^2A)(sin^2A-cos^2A)
sin^2A+cos^2A=1
1(sin^2A-cos^2A)
-(cos^2A-sin^2A)
Ans: -cos2A
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