prove sin^4a+2sin^2acos^2a+cos^4a=1
Answers
Answered by
1
Step-by-step explanation:
[sin^2(a) + cos^2(a)]^2
= 1
Answered by
4
Take the LHS.
sin⁴a + 2 sin²a cos²a + cos⁴a
This seems in the form x² + 2xy + y², where x = sin²a and y = cos²a.
This is the expanded form of (x + y)², isn't it?
So we get,
sin⁴a + 2 sin²a cos²a + cos⁴a = (sin²a + cos²a)².
We are very much familiar with this one.
sin²a + cos²a = 1.
This is because,
sin²a + cos²a
⇒ (opposite side of angle a / hypotenuse)² + (adjacent side of angle a / hypotenuse)²
⇒ ((opposite side of angle a)² + (adjacent side of angle a²)) / hypotenuse²
⇒ hypotenuse² / hypotenuse² [Right triangle is considered, so base² + altitude² = hypotenuse²]
⇒ 1
So,
(sin²a + cos²a)² = 1² = 1 which is the RHS.
Hence Proved!
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