Question

PRove
sin(A-B)=SinA.CosB-cosA.sinB
value of A=60 and B=60

Answer 1

LHS = sin(A-B)

= sin(60-60)

= sin0

= 0

RHS = SinA.CosB-cosA.sinB

= sin60.cos60 - cos60sin60

= √3/2 × 1/2 - 1/2 × √3/2

= 0

Thus, LHS = RHS.

Answer 2

Step-by-step explanation:

RHS:-

Sin(A-B)

LHS:-

SinA.CosB - CosA.SinB

Sin60.Cos60 - Cos60.Sin60

Root3/2. 1/2 - 1/2. Root3/2

Root3/4 - Root3/4

By subtracting it we get :-

0/4

= 0

RHS:-

Sin(60-60)

= 0

Therefore,

LHS=RHS(0=0)

Hence PROVED.