prove Sin A +Sin B +sin C=S/R
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t his is the correct answer for the question
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We know a/sinA=b/sinB=c/sin
C=2R
So a/(2R)=sinA b/(2R)=sinB c/(2R)=sinC
Now sinA+sinB+sinC =1/(2R)[a+b+c) =2s/
(2R)=s/R proved
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