Prove sin A tan A /1-cos A =1+sec A
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sinAtanA/1-cosA=
sinA*sinA/1-cosA(cosA)
sin^2A/(1-cosA)cosA
1-cos^2A/1-cosA(cosA)
(1+cosA)(1-cosA)/1-cosA(cosA)
(1+cosA)/cos
separate the numerator
=1+secA
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