Math, asked by kjhanvi875amne, 8 months ago

Prove sin A tan A /1-cos A =1+sec A

Answers

Answered by suryanshipathak

1

sinAtanA/1-cosA=

sinA*sinA/1-cosA(cosA)

sin^2A/(1-cosA)cosA

1-cos^2A/1-cosA(cosA)

(1+cosA)(1-cosA)/1-cosA(cosA)

(1+cosA)/cos

separate the numerator

=1+secA

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