Prove sin2 theta+cos2 theta=1
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Answer:consider a right angle triangle ABC
Take B as 90degree
Now AB/AC=sin tetha
And BC/AC=cos tetha
Therefore, from given
(AB)^2/(AC)^2+(BC)^2/(AC)^2
We in a right angle triangle
AB+BC=AC
Hence proved
Step-by-step explanation:
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