Prove sin²A +cos²A=1 , sec²A=1+tan²A and cosec²A=1+cot²A. prove with taking an diagram as example as proof.
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Answer:
Sin²A.cot²A+cos²A.tan²A =Sin²A.cos²A/sin²A +cos²A.sin²A/cos²A =Cos²A+Sin²A =1 Proved
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Answer:
1. sin²A + cos²A = 1
value of sin is p/h
value of cos is b/h
- LHS
- sin²A + cos²A
- (p/h)² + (b/h)²
- p²/h² + b²/h²
- (p²+b²)/h²
- h²/h²
- 1. RHS
2. 1 + tan²A = sec²
we know that tan is p/b
sec is h/b
- LHS,
- 1 + tan²A
- 1 + (p/b)²
- 1 + p²/b²
- (b² + p²) / b²
- h²/b²
- sec²A RHS
3. 1 + cot²A = cosec²A
we know that cot is b/p
cosec is h/p
- LHS,
- 1 + cot²A
- 1 + (b/p)²
- 1 + b²/p²
- (p² + b²) / p²
- h²/p²
- cosec²A RHS
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