Math, asked by dhanush1646, 5 months ago

Prove sin²A +cos²A=1 , sec²A=1+tan²A and cosec²A=1+cot²A. prove with taking an diagram as example as proof.

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Answers

Answered by crackmehkma7172
0

Answer:

Sin²A.cot²A+cos²A.tan²A =Sin²A.cos²A/sin²A +cos²A.sin²A/cos²A =Cos²A+Sin²A =1 Proved

Answered by adityashah0755
2

Answer:

1. sin²A + cos²A = 1

value of sin is p/h

value of cos is b/h

  • LHS
  • sin²A + cos²A
  • (p/h)² + (b/h)²
  • p²/h² + b²/h²
  • (p²+b²)/h²
  • h²/h²
  • 1. RHS

2. 1 + tan²A = sec²

we know that tan is p/b

sec is h/b

  • LHS,
  • 1 + tan²A
  • 1 + (p/b)²
  • 1 + p²/b²
  • (b² + p²) / b²
  • h²/b²
  • sec²A RHS

3. 1 + cot²A = cosec²A

we know that cot is b/p

cosec is h/p

  • LHS,
  • 1 + cot²A
  • 1 + (b/p)²
  • 1 + b²/p²
  • (p² + b²) / p²
  • h²/p²
  • cosec²A RHS

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