prove: sin²Acos²B-cos²A-sin²B=sin²A-sin²B
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L.H.S=Sin²A(1-Sin²B)-(1-Sin²A)Sin²B
=Sin²A-Sin²ASin²B-Sin²B+Sin²ASin²B
=Sin²A-Sin²B
=R.H.S
=Sin²A-Sin²ASin²B-Sin²B+Sin²ASin²B
=Sin²A-Sin²B
=R.H.S
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