Math, asked by Anonymous, 1 year ago

prove :- sin²Acos²B-cos²Asin²B=sin²A-sin²B

Answers

Answered by rudra09

5

Step-by-step explanation:

refer to the attachment.......

Attachments:

Answered by abhinavnayan18

2

Hola Dear ❤❤

LHS = ( Sin² A Cos² B - Cos²A Sin² B )

=> Sin²A ( 1 - Sin²B ) - ( 1 - Sin²A ) Sin²B

=> ( Sin²A - Sin²B ) = RHS.

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