prove sin2x+cos2x is equal to 1
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Answer:
sinx=P/H
cosx=B/H
sin^2x+cos^2x
(P/H) ^2+(B/H)^2
we take H^2as LCM then we add it
P^2+B^2/H^2
as we know in a right angled triangle base square+perpendicular square equal to hypotenuse square
H^2/H^2=1
hence, proved
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Answer:
answer for the given problem is given
Step-by-step explanation:
Pythagoras Theorem:
In a right angled triangle,the square of hypotenuse is equal to the sum of the squares of the other two sides.
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