Math, asked by bvarghese42, 6 months ago

prove sin2x+cos2x is equal to 1

Answers

Answered by sandeep2151919
0

Answer:

sinx=P/H

cosx=B/H

sin^2x+cos^2x

(P/H) ^2+(B/H)^2

we take H^2as LCM then we add it

P^2+B^2/H^2

as we know in a right angled triangle base square+perpendicular square equal to hypotenuse square

H^2/H^2=1

hence, proved

Answered by tennetiraj86
2

Answer:

answer for the given problem is given

Step-by-step explanation:

Pythagoras Theorem:

In a right angled triangle,the square of hypotenuse is equal to the sum of the squares of the other two sides.

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