Prove:
Sin³ A-8 / sin A-2 = sin²A +2sinA+4
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Step-by-step explanation:
sin³A-8/sinA-2
=sin³A-2³/sinA-2
=(sinA-2)(sin²A+2sinA+2²)/(sinA-2)
[using a³-b³=(a-b)(a²+ab+b²)]
=sin²A+2sinA+4
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