Math, asked by gokulzealot, 1 year ago

Prove sin4A=4sinA cos³A-4cosA sin³A

Answers

Answered by mathgodnabarun

5

sin(A+A+A+A)= sin4A = sin(A+A)cos(A+A)+cos(A+A)sin(A+A).
=> sin2Acos2A+cos2Asin2A.
=> 2sinAcosA(cos²A-sin²A)*2
=> 4sinAcos³A-4sin³AcosA
hence proved.

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