Question

Prove : (sinA +cosA)^2=1+sin2A

Answer 1

Step-by-step explanation:

hope u understand.....

Answer 2

Solution

LHS (SinA+cosA)^2

sin^2A+2SinA.cosA+cos^2A

sin^2A+cos^2A+2SinA.CosA

1+2SinA.CosA. (sin^A+cos^2A=1)

1+SinA.CosA+SinA.CosA

1+sin(A+A). ( sin(A+B)=SinA.cosB+SinB.cosA)

1+sin2A

RHS=1+sin2A

LHS=RHS

hence proved