Question

prove sinA×cosA (tanA+cotA)=1 ​

Answer 1

sinAcosA((sinA/cosA)+(cosA/sinA))

=sinAcosA(sin²A+cos²A/sinAcosA)

=sin²A+cos²A

=1

SO SIMPLE DUDE

❅❅❅❅❅❅❅❅❅

ʜᴏᴘᴇ ⁱᵗ ʜᴇʟᴘs ʏᴏᴜ 

Answer 2

sina*cosa(sina/cosa+cosa/sina)

• sina*cosa(sin^a+cos^a/sina*cosa)
• sin^a+cos^a=1
• hence proved