Math, asked by yash0734, 3 months ago

. Prove :
sinA/cotA+cosecA=2+sinA/cotA-cosecA

Answers

Answered by Ashely607S

1

Answer:

⇒ LHS =

sinA/(cotA+cosecA)

= (sinA)(cosecA-cotA)/(cosecA+cotA)(cosecA-cotA)

= (1-cosA)/(cosec2A-cot2A)

= (1-cosA)/1 = 1-cosA

⇒ RHS =

2+(sinA)/(cotA-cosecA)

= 2+(sinA)(cotA+cosecA)/(cotA-cosecA)(cotA+cosecA)

= 2+(cosA+1)/(cot2A-cosec2A)

= 2+(cosA+1)/(-1)

= 2-cosA-1

= 1-cosA

LHS=RHS=1-cosA

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