prove sum of all natural numbers = -1/12
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Answered by
3
Answer:
Step-by-step explanation:
120
Let
S=1+2+...+(n−1)+n.
Write it backwards: S=n+(n−1)+...+2+1. Add the two equations, term by term; each term is n+1, so
2S=(n+1)+(n+1)+...+(n+1)=n(n+1).
Divide by 2:
S=n(n+1)2
ryzenOP:
its not full explanation
Answered by
3
Answer:
Step-by-step explanation:
120
Let
S=1+2+...+(n−1)+n.
Write it backwards: S=n+(n−1)+...+2+1. Add the two equations, term by term; each term is n+1, so
2S=(n+1)+(n+1)+...+(n+1)=n(n+1).
Divide by 2:
S=n(n+1)2
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