prove.. tan^2A+cot^2A=sec^2A+cosec^2A
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Answer:
LHS=tan
2
A+cot
2
A
=
cos
2
A
sin
2
A
+
sin
2
A
cos
2
A
=
sin
2
Acos
2
A
sin
4
A+cos
4
A
=
sin
2
Acos
2
A
(sin
2
A+cos
2
A)
2
−2sin
2
Acos
2
A
=
sin
2
Acos
2
A
1−2sin
2
Acos
2
A
=
cos
2
A
1
.
sin
2
A
1
−2
=sec
2
A.cosec
2
A−2
=RHS
Hence proved
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