Prove.
tan 55=
(Cos 10° + Sin 10°)/
(cos 10° - Sin 10°)
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You mean [cos(10)+sin(10)]/[cos(10) - sin(10)].
The "order of operations" calls for multiplications and divisions to be done before additions and subtractions, so what you typed would put ONLY the sin(10) in the numerator and ONLY the cos(10) in the denominator.
Anyway, tan(55) = tan(45 + 10)
= [tan(45) + tan(10)]/[1 - tan(45)tan(10)]
= [1 + tan(10)] / [1 - tan(10)]
Now multiply all 4 terms by cos(10), and you get
[cos(10) + sin(10)]/[cos(10) - sin(10)].
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