prove : (tanθ + sinθ + 1)(tanθ - secθ + 1) /tanθ = 2
Anonymous:
I suggest you check the question again.
actually this ques was in SA1 examination cbse 2014
This means, it should satisfy for every angle in place of theta.
Try theta=45 degrees
You get L.H.S. = 3-√2 which is not equal to R.H.S.
Maybe, it's sec in place of sin.
You get to prove it if there was sec in place of sin
you are probably right jackie.. so assume that there is sec theta in the numerator in place of sine theta. and answer it
The questioner says it was given in cbse examination
im so sry ... i consulted my teacher n i came 2 knw that the ques is wrng..!!..sry 4 makin u trouble..
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It is sec instead of sin. Now consider the numerator it can be written as [(tanA+1)+(secA)][(tanA+1)-(secA)] = (1+tanA)²-(secA)²=1+tan²A+2tanA-1-tan²A=2tanA.
Hence you have 2tanA/tanA=2.
you should write clearly each expression on a different line..
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