Prove :
tan θ sin θ + cos θ = sec θ
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Solution :
Let A = tan θ sin θ + cos θ and B = sec θ.
A = tan θ sin θ + cos θ
A = (sin θ/cos θ) ⋅ sin θ + cos θ
A = (sin2θ/cos θ) + cos θ
A = (sin2θ/cos θ) + (cos2θ/cosθ)
A = (sin2θ + cos2θ) / cos θ
A = 1 / cos θ
A = sec θ
A = B (Proved)
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Step-by-step explanation:
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