Question

Prove :

tan θ sin θ + cos θ  =  sec θ

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Answer 1

Solution :

Let A = tan θ sin θ + cos θ and B = sec θ.

A = tan θ sin θ + cos θ

A = (sin θ/cos θ) ⋅ sin θ + cos θ

A = (sin2θ/cos θ) + cos θ

A = (sin2θ/cos θ) + (cos2θ/cosθ)

A = (sin2θ + cos2θ) / cos θ

A = 1 / cos θ

A = sec θ

A = B (Proved)

Answer 2

Step-by-step explanation:

hope it helps you friend!