Math, asked by faraanahmedhashmi, 11 months ago

prove
tan2A= (sec2A + 1)(tanA)

Answers

Answered by yash12384

1

Step-by-step explanation:

tan2A=(sec2A+1)(tanA)

R.H.S=(sec2A+1)(tanA)

=(1/cos2A+1)(sinA/cosA)

=(cos2A+1/cos2A)×(sinA/cosA)

=(2cos^2A/cos2A)

=2sinA.cosA/cos2A

=sin2A/cos2A

=tan2A

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