Math, asked by n9a8n1d0i9n1i, 4 days ago

prove.
tan²Q-sin²Q =tan²Qsin²Q

Answers

Answered by veenagoswami65

0

Step-by-step explanation:

tan²Q = tan²Qsin²Q+sin²Q

tan²Q= sin²Q(tan²Q+ 1)

tan²Q = sin²Q(sec²Q)

tan²Q= sin²Q /cos²Q

tan²q= tan²q

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