Math, asked by sssbkara, 1 year ago

Prove tan3x*tan2x*tanx=tan3x-tan2x-tanx

Answers

Answered by surendra05044
3

Answer:

proof:

put: tanx=tan(3x-2x)

now:

tan(3x-2x)= tan3x-tan2x/1+tan3xtan2x

tanx(1+tan3xtan2x)=tan3x-tan2x

tanx+tan3xtan2xtanx=tan3x-tan2x

tan3xtan2xtanx=tan3x-tan2x-tanx

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