prove tan⁴x+tan²x=sec⁴x-sec²x
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Answer:
LHS=tan⁴A+tan² RHS=sec²A-sec²A
Step-by-step explanation:
LHS=tan²A(tan²A+1)
as(1+tan²A=sec²A)
LHS= (1-sec²A)(sec²A)
LHS= sec²A-sec⁴A=RHS
Hence, proved.
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