Math, asked by sanukadam721, 10 months ago

prove tan⁴x+tan²x=sec⁴x-sec²x​

Answers

Answered by yash8853
4

Step-by-step explanation:

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Answered by ShresthaTheMetalGuy
4

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Answer:

LHS=tan⁴A+tan² RHS=sec²A-sec²A

Step-by-step explanation:

LHS=tan²A(tan²A+1)

as(1+tan²A=sec²A)

LHS= (1-sec²A)(sec²A)

LHS= sec²A-sec⁴A=RHS

Hence, proved.

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