prove: TanA+2Tan2A+4Tan4A+8Cot8A=CotA
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Step-by-step explanation:
Consider: Cot A - Tan A - 2 Tan 2 A
We know Cot A - Tan A
= cos²-sin²A / cin A. cos A = 2 cot 2 A
= 2 cot 2 A - 2 Tan 2 A
= 2 (cot 2 A - tan 2 A)
=2 (2cot 4 A)
4 cot 4 A
Similarly: Cot A - tan A - 2 Tan A - 4 tan 4 A
= 4 cot 4 A - 4 tan 4 A
= 4 (cot 4 A - tan 4 A)
= 8 cot 8 A
i.e, cot A - tan A - 2tan A - 4 tan 4 A = 8 cot 8 A
So, Tan A + 2 Tan A + 4 Tan 4 A + 8 Cot 8 A = Cot A
Answer is Cot A.
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