Question

prove:
$1 - \cos(2theta) \div 1 + \cos(2theta) = \tan( {theta}^{2} )$

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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

1 - Cos2θ/ 1 + Cos2θ

using identity Cos2θ = Cos²θ - Sin²θ = 2Cos²θ - 1 = 1 - 2Sin²θ.

= 1 - (1 - 2Sin²θ) / 1 + (2Cos²θ - 1)

= 1 - 1 + 2Sin²θ/ 1 - 1 +  2Cos²θ

= 2Sin²θ/2Cos²θ

= Tan²θ

= R.H.S.

Hence proved