Math, asked by stuti0041, 2 months ago

Prove:
 {  3}^{ - 3}  \times  {6}^{2}  \times  \sqrt{98 } \div  {5}^{2} \times  \sqrt[3]{1 \div 25} \times  {15}^{ - 4 \div 3}  \times  {3}^{1 \div 3}
is equal to
28 \sqrt{2}



Answers

Answered by ariRongneme
2

Here is your answer, buddy.

The answer are given above the attachment.

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