Question

Prove :- $\bf \displaystyle \lim_{x\to a} \bf \bigg( \dfrac{x²-a²}{x-a} \bigg) = 2a [tex]\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ From epsilon delta definition of limit which states that , for any [tex] \varepsilon > 0$ , there exist a +ve no. $\delta$ such that ${ \bf 0 < | x - a | < \delta }$ , then ${ \bf | f ( x ) - l | < \varepsilon }$ Range of x and f(x) are as follows $\leadsto \bf f ( x ) \in ( l - \varepsilon , l + \varepsilon )$ $\leadsto \bf x \in ( a - \delta , a + \delta )$ ​

Answer 1

if 3% is 0

then hence proved

Answer 2

Answer:

if 3% is x

Step-by-step explanation:

hence proveddd