Question

prove
$\sqrt{3 } + \sqrt{5}$
irrational​

Answer 1

$\huge\bold\red{Answer:}$

Let √3+√5 be rational

√3+√5=a/b (a rational number)

S.O.B.S

3+5+2√15=(a/b)²

2√15=(a/b)²-8

√15=½[(a/b)²-8]

Since an irrational cannot be equal to rational

Hence our assumption that √3+√5 is wrong

Therefore √4

√3+√5 is irrational