Question

Prove :
$\ \textless \ br /\ \textgreater \ \sf{ \dfrac{cos \: \theta}{sin \: \theta} = \dfrac{ \sin \: \cos}{x} }\ \textless \ br /\ \textgreater \ ​$
​

Answer 1

Answer:

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In classical physics and general chemistry, matter is any substance that has mass and takes up space by having volume

Answer 2

Given that

: 0≤x≤ 2π

and

sin2x

– COSX

cos2x + sinx

We know

sin2x 2 sinx cosx

and

0

1

cos2x

1

2sin²x

On substituting the identity of sin2x in numerator and cos2x in denominator, we get

2sinxcosx – COSX

2sin²x + sinx

2sinxcosx – COSX

:

1

0

1

- 2sin²x + sinx - 1 = 0

2sinxcosx

COSX

- 2sin²x + sinx

0

cosx (2sinx−1 −sinx (2sinx−1) 0

- cotx

• cotx = 0

0: cotx = 0

3T 2 X = or 2

Verification :

Given equation is

sin2x – COSX

cos2x + sinx — 1

: When x =

2

On substituting the value in above equation, we get

sint COST + sin COS : 2 = 0 1 2

0-0

−1+1-1

0 −1 0

= 0Hence, verified

Now,

Again, Given equation is

sin2x – COSX

- cos2x + sinx 1 0

: When x =

2

sin37 COS

3π

2

3π

cos3π sin- 1

2

0 0 −1+1−1 → = 0

0 -1 0

0 0

Hence, Verified

Additional Information :

Additional Information :

T eq

sinx 0

COSX = 0

tanx = 0

sinx = siny

cosx = cosy

X =

Solution

x = nπ Vn € Z

X = ㅠ (2n+1) Z

x = nπ Vn €Z

x = nπ + (-1)"y Vn € Z

2nπ ±y Vn € Z x = n²+y\n € Z