prove tha Sin 2x(tanx+cotx)=2
odi:
just write cotx=1/tanx and sin2x=2sinxcosx u will surely get ur answer
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here is your answer
L.H.S.
Sin2x (tanx+cotx)
2sinxcos x ( sinx/cosx + cosx/sinx) { Sin2A = 2sinx cos x}
{ tanx= sinx/cosx , cot = cosx/sinx}
2sinx cosx ( sin^2x + cos^2x/ cosx sinx)
{sin & cos are cancel }
2 × (sin^2x + cos^2x) { sin^2x+ cos^2x =1}
2 ×1
2
L.H.S.=R.H.S
it can help you ✌
L.H.S.
Sin2x (tanx+cotx)
2sinxcos x ( sinx/cosx + cosx/sinx) { Sin2A = 2sinx cos x}
{ tanx= sinx/cosx , cot = cosx/sinx}
2sinx cosx ( sin^2x + cos^2x/ cosx sinx)
{sin & cos are cancel }
2 × (sin^2x + cos^2x) { sin^2x+ cos^2x =1}
2 ×1
2
L.H.S.=R.H.S
it can help you ✌
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