Question

prove thaat 1+secA/secA=sinsquareA/1-cosA​

Answer 1

Hi ,

LHS = ( 1 + secA )/secA

= ( 1 + 1/cosA ) / ( 1/cosA )

= [ ( CosA + 1 ) / cosA ] / ( 1/ cosA )

= Cos A + 1

= ( 1 + cosA ) ( 1 - cosA ) / ( 1 - cosA )

= ( 1 - cos² A ) / ( 1 - cosA )

= Sin² A / ( 1 - cosA )

= RHS

hope this answer helpful u