prove Thales theorem
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thanks.......................
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Hey mate....
here's your answer.......
In triangle ABC ,
DE || BC
AD /DB = AE /EC ( by basic proportionality theorem)
x /(x - 2) = (x + 2) /(x - 1)
x (x - 1) = (x - 2)(x + 2) (by cross multiplication)
x2 - x = x2 - 4
-x = -4
x = 4
Hope it helps ⭐
here's your answer.......
In triangle ABC ,
DE || BC
AD /DB = AE /EC ( by basic proportionality theorem)
x /(x - 2) = (x + 2) /(x - 1)
x (x - 1) = (x - 2)(x + 2) (by cross multiplication)
x2 - x = x2 - 4
-x = -4
x = 4
Hope it helps ⭐
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