Question

Prove that {(0.6)^0-((0.1)^-1)}/[{(3/8)^-1×(3/2)^3}+(-1/3)^-1]=-3/2

Answer 1

Answer:

please refer attached image

Answer 2

Answer:

Proved by solving LHS = RHS.

Step-by-step explanation:

let's solve this by taking LHS

${(0.6)^0-((0.1)^-1)}/[{(3/8)^-1×(3/2)^3}+(-1/3)^-1] \\ {(1 - 1 \div 01)}/[{(8/3)×(3/2)^3}+(-3/1)] \\ = {1 - 1 \div 01)}/[{( {3}^{2} - 3 )]} \\ = {1 - 1 \div 01)}/[{( 9 - 3 )]} \\ = {1 - 1 \div 01)}/[{( 6)]} \\ = {(1 \div 6 - 1 \div 0.6) \times 10 \div 10} \\ = 1 - 10 \div 6 \\ = - 9 \div 6 \\ = - 3 \div 2$

hence ,

LHS = RHS

$-3/2 = -3/2 .$

(#SPJ2)