prove that 0.75*0.75*0.75+0.25*0.25*0.25/0.75*0.75-0.75*0.25+0.25*0.25=1
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0.75³+0.25³/.75²+.25²-.75×.25
=(.75+.25)(0.75²+0.25²-0.75×0.25)/(0.75²+0.25²-0.75×0.25)=0.75+0.25=1.00=1
(a³+b³=(a+b)(a²+b²-ab)
=(.75+.25)(0.75²+0.25²-0.75×0.25)/(0.75²+0.25²-0.75×0.25)=0.75+0.25=1.00=1
(a³+b³=(a+b)(a²+b²-ab)
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