Question

prove that 0.85×0.85×0.85+0.15×0.15×0.15/0.85×0.85-0.85×0.15+0.15×0.15=1.

Answer 1

Hola Mate !!

Here's your answer :-

$lhs - \\ \frac{0.85 \times 0.85 \times 0.85 + 0.15 \times 0.15 \times 0.15}{0.85 \times 0.85 - 0.85 \times 0.15 + 0.15 \times 0.15 } \\ = > \frac{ {(0.85)}^{3} + ( {0.15)}^{3} }{ {(0.85)}^{2} - 0.85 \times 0.15 + {(0.15)}^{2} } \\ = > \frac{(0.85 + 0.15)(( {0.85}^{2} - 0.85 \times 0.15 + ( {0.15)}^{2} )}{( {0 .85)}^{2} - 0.85 \times 0.15 + ( {0.15)}^{2} } \\ = > 0.85 + 0.15 = 1(rhs)$

Hence, proved.

Hope it helps
Mark me as brainliest if it's correct

Answer 2

Answer:

Step-by-step explanation:

a=0.85

b=0.15

a³+b³/a²-ab+b²

(a+b)(a²-ab+b²)/(a²-ab+b²)

substitute

(a+b)=(0.85+0.15)=1