Question

Prove that 1=0 using a&b method​

Answer 1

Expanding the l.h.s. gives(a∗b)∗c=(a+b−ab)∗c=(a+b−ab)+c−(a+b−ab)c=a+b+c−bc−ca−ab+abc.

Now, do the same thing for the r.h.s. and verify that the expressions agree.

stop doing this..

Answer 2

Answer:

Mathematically, there is a anomaly behind the solution I am going to state below:

Step -1: Let’s take 4=4 (This is not a Anomaly, but is a fact unlike 0=1)

Step-2: Now (2)^2 = (-2)^2 (Square of both positive and negative number results in positive sign numbers)

Step-3: Taking Square root both sides, we get -2 = 2 (Square root will negate the power 2 of both sides)

Step-4: Now, what do we see: -2 =2 which is 4=0 (by taking -2 on other side)

Now you can prove 0 equal to any number by multiplying or dividing both the sides.

Incorrect step here is step 3 where we negate the square root with the power since both the numbers having different signs cannot be equal. This is the anamoly