Prove that
1 1 1
x y z
x`3 y`3 z`3
= x-y y-z z-x x+y+z
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Answer:
Identity:x3 +y3 +z3 -3xyz = (x+y+z)( x2 +y2 +z 2 -xy-yz-zx). Since x + y + z = 1, xy + yz + zx = -1and xyz= -1,. Putting values, we get: So.
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