Prove that (1, 1) (4, 4) and (6, 2) are the vertices of a right angled triangle.
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let A(1,1) B(4,4) c(6,2) are the vertices of a ryt angled traingle
by distance formula
AB=√(4-1)2+(4-1)2√= (3)2+(3)2= 9+9=10
BC= √(6-4)2+(2-4)2= (2)2-(2)2=4-4= 0
AC= √(6-2)2+(2-1)2=( 4)2+(1)2= 16+1=17
no this is not a ryt angled traingle
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